Bradbury uuuu to uuuu 859/236/97/85923697.geojson

Bradbury is a locality and its consensus geometry is derived from quattroshapes.

Properties

{"name:epo_x_preferred":["Bradbury"],"name:uzb_x_preferred":["Bradbury"],"name:heb_x_preferred":["ברדבורי"],"geom:latitude":34.153545,"name:vol_x_preferred":["Bradbury"],"wof:name":"Bradbury","name:ceb_x_preferred":["Bradbury"],"wd:wordcount":1730,"name:ara_x_preferred":["برادبوري"],"name:azb_x_preferred":["برادبوری"],"name:srp_x_preferred":["Бредбери"],"wof:geom_alt":["quattroshapes_pg"],"name:hun_x_preferred":["Bradbury"],"qs:id":0,"name:swa_x_preferred":["Bradbury"],"counts:concordances_total":8,"qs:adm0":"United States","geom:type":"Polygon","wof:lastmodified":1722116154,"qs:a1":"*California","wof:belongsto":[102191575,85633793,102086957,85688637],"name:rus_x_preferred":["Брэдбери"],"mps:latitude":34.156126,"qs:a0":"United States","wof:repo":"whosonfirst-data-admin-us","wof:country":"US","name:nob_x_preferred":["Bradbury"],"name:swe_x_preferred":["Bradbury"],"wof:breaches":[],"edtf:inception":"uuuu","iso:country":"US","geom:bbox":"-117.985867,34.143618,-117.951279,34.165159","qs:loc_lc":"0607946","src:lbl_centroid":"mapshaper","name:fra_x_preferred":["Bradbury"],"wof:geomhash":"505fd16a2039ac1668effd0315e56d53","name:fas_x_preferred":["بردبری، کالیفرنیا"],"name:che_x_preferred":["Бредбери"],"mz:is_ceased":0,"name:nan_x_preferred":["Bradbury"],"lbl:max_zoom":16,"src:population":"uscensus","src:population_date":"2023","wof:placetype":"locality","name:mlg_x_preferred":["Bradbury"],"name:zho_x_preferred":["白普理"],"gn:longitude":-117.9709,"name:dan_x_preferred":["Bradbury"],"wof:population":892,"name:new_x_preferred":["ब्र्याडब्युरी"],"name:war_x_preferred":["Bradbury"],"name:eus_x_preferred":["Bradbury"],"qs:source":"AUS Census","name:lld_x_preferred":["Bradbury"],"name:mal_x_preferred":["ബ്രാഡ്‍ബറി"],"name:hbs_x_preferred":["Bradbury"],"wof:concordances":{"fct:id":"08bfdab0-8f76-11e1-848f-cfd5bf3ef515","fips:code":"0607946","gn:id":5330443,"gp:id":2367789,"qs_pg:id":158616,"uscensus:geoid":"0607946","wd:id":"Q896910","wk:page":"Bradbury, California"},"qs:a1r":"*","name:arz_x_preferred":["برادبورى"],"name:cat_x_preferred":["Bradbury"],"src:geom_alt":["quattroshapes_pg"],"name:pol_x_preferred":["Bradbury"],"wof:tags":[],"name:urd_x_preferred":["بریڈبری"],"wof:population_rank":2,"wof:supersedes":[],"lbl:longitude":-117.968028,"edtf:cessation":"uuuu","name:deu_x_preferred":["Bradbury"],"gn:population":1048,"qs:loc_alt":"Bradbury city","counts:names_total":45,"mz:is_current":1,"wof:hierarchy":[{"continent_id":102191575,"country_id":85633793,"county_id":102086957,"locality_id":85923697,"region_id":85688637}],"name:fas_x_variant":["بردبری"],"gn:elevation":206,"mz:min_zoom":11,"lbl:latitude":34.156126,"lbl:min_zoom":12,"name:por_x_preferred":["Bradbury"],"geom:area":4.96E-4,"wd:population":1048,"gn:latitude":34.14695,"name:tat_x_preferred":["Бредбери"],"name:hrv_x_preferred":["Bradbury"],"wof:lang":["eng"],"qs:loc":"Bradbury","counts:names_preferred":44,"geom:area_square_m":5074772.309003,"counts:names_variant":1,"name:ukr_x_preferred":["Бредбері"],"name:spa_x_preferred":["Bradbury"],"name:eng_x_preferred":["Bradbury"],"wd:elevation":206,"wof:superseded_by":[],"name:nld_x_preferred":["Bradbury"],"qs:pop":0,"wof:placetype_id":102312317,"qs:la_lc":"*","qs:level":"locality","name:ita_x_preferred":["Bradbury"],"mz:is_deprecated":0,"name:tgl_x_preferred":["Bradbury"],"wd:latitude":34.149444,"qs:type":"G4110","geom:longitude":-117.968357,"wof:id":85923697,"src:geom":"quattroshapes","name:bul_x_preferred":["Брадбъри"],"counts:names_languages":44,"name:tur_x_preferred":["Bradbury"],"uscensus:population":892,"name:hat_x_preferred":["Bradbury"],"mps:longitude":-117.968028,"qs:a1_lc":"06","uscensus:population_date":"2023","wof:parent_id":102086957,"wof:placetype_names":["locality"],"mz:hierarchy_label":1,"name:gle_x_preferred":["Bradbury"],"wd:longitude":-117.974444}
Hierarchy
Other